Abc is a quadrant of a circle of radius 14 cm. Dec 13, 2024 · Ex 12.

Abc is a quadrant of a circle of radius 14 cm. cm. ___ View Solution In the given figure, ABC is a quadrant of a circle of radius 14 cm and a semicircle is drawn with BC as diameter. In the following figure A B C is a quadrant of a circle of radius 14cm and a semicircle is drawn with B C as diameter. Jul 21, 2023 · In the figure, ABC is a right angled triangle with B = 90∘ , BC = 21 cm and AB = 28 cm. Find the area of the shaded region - In the given figure, ∆ABC is a right-angled triangle with ∠B = 90°, AB = 48 cm and BC = 14 cm. Find the area of the shaded region (in cm2). Find the area of the shaded region Solution: We use the formula for areas of semi-circles and sector of circles to solve the problem. Feb 13, 2023 · Solution For In Fig. = 16 – 4 × 0. (Take π = 22 7) Mar 19, 2018 · In the figure, ABC is a quadrant of a circle of radius 14 cm and a semicircle is drawn with BC as diameter. With AC as diameter, a semicircle is drawn. 3 Q15Q: In Fig. Dec 13, 2024 · Ex 12. 78 – 3. In Fig. 74 sq. In the given figure, ABC is a quadrant of a circle of radius 14 cm and a semicircle is drawn with BC as diameter. Solution: Radius of the circle r In the figure, AB and CD are two diameters of a circle (with centre O) perpendicular to each other and OD is the diameter of the smaller circle. Question 6. [2 MARKS]You visited us 1 times! Enjoying our articles? Unlock Full Access! In the given figure, ABC is a quadrant of a circle of radius 14 cm and a semicircle is drawn with BC as diameter. 47 cm2 72 cm2 98 cm2 None of these Aug 3, 2018 · In the given figure, ABC is a quadrant of a circle of radius 14 cm and a semicircle is drawn with BC as diameter. 3 Class 10 Maths Question 10. 12. , ABC is a quadrant of a circle of radius 14cm and a semicircle is drawn with BC as diameter. With AC as diameter a semicircle is drawn and with BC as radius, A quadrant of a circle is drawn. Find the area of the shaded region In the given figure, ABC is a quadrant of a circle of radius 14 cm and a semicircle is drawn with BC as diameter. 12 – 3. ABCP is a quadrant of a circle of radius 14 cm. 5 cm2. We have the following formulae,Area of semi-circle = π r 2 2 Area of quadrant = π r 2 4 Area of triangle = 1 2 ×b×h We have,AB = AC = 14cm ∴BC=14 2 =2× radius radius = 14 2 2 r=7 2 cm Area of the semi-circle will be, = 1 2 × 22 7 ×7 2 ×7 2 =154 cm 2 Area of the quadrant will be The key information is that ABC is a quadrant of a circle with a 14 cm radius, and a semicircle is drawn with BC as its diameter. If OA = 7 cm, find the area of the shaded region. 33. Find the area of the shaded portion (figure). Find the area of the shaded region. For Short The correct answer is Given that the radius of a circle is 14 cm and BC is the diameter of a semi-circle. In a circular table cover of radius 32 cm, a design is formed leaving an equilateral triangle ABC in the middle as shown in the given figure. In the figure, ABC is a quadrant of a circle of radius 14 cm and a semicircle is drawn with BC as diameter. 3, 15 In figure, ABC is a quadrant of a circle of radius 14 cm and a semicircle is drawn with BC as diameter. by Maths experts to help you in doubts & scoring excellent marks in Class 10 exams. Jul 21, 2023 · In the given figure, ABC is a quadrant of a circle of radius 14 cm and a semicircle is drawn with BC as diameter. Jul 21, 2023 · In Fig. Feb 12, 2025 · Solution For olve the following sub-questions (Any one): In the given figure, ABC is a quadrant of a circle of radius 14 cm and a semicircle is drawn with BC as diameter. 33, ABC is a quadrant of a circle of radius 14 cm and a semicircle is drawn with BC as diameter. Solution: Radius of the bigger circle = 7 cm Ex 12. The area of an equilateral triangle ABC is 17320. BC is also the radius of the quadrant, so BC = 14 cm. Jul 21, 2023 · Step by step video & image solution for In Fig. Dec 26, 2020 · 15. [Use π = 22/7] Feb 8, 2019 · ABCP is a quadrant of a circle of radius 14 cm. 14 = 16 – 3. Nov 4, 2020 · In the figure, ABC is a quadrant of a circle of radius 14cm, and a semicircle is drawn with BC as diameter. With AC as diameter of a semicircle and with BC as radius, a quarter circle is drawn. [Use Π = 22/7] In the figure, ABC is a right angled triangle with B = 90∘ , BC = 21 cm and AB = 28 cm. In figure, ABC is a quadrant of a circle of radius 14 cm and a semicircle is drawn with BC as diameter. The radius of the semicircle is half of BC, which is 7 cm. 26 = 9. Find the area of Oct 4, 2018 · In given figure ABPC is a quadrant of a circle of radius 14 cm and a semicircle is drawn with BC as diameter. 14 = 16 – 6. Find the area of the shaded portion. ABC is a quadrant of a circle of radius 20 cm and a semicircle is drawn with BC as diameter. Dec 16, 2024 · In given figure ABPC is a quadrant of a circle of radius 14 cm and a semicircle is drawn with BC as diameter. 12. [2 MARKS] Question 15 In Fig. . Nov 9, 2021 · ABC is a quadrant of a circle of radius 14 cm and a semicircle | Ch 12 Class 10 Maths Ex 12. Find the area of the design. Area of shaded region = Area of semicircle BEC – (Area of quadrant ABDC – Area of Δ ABC) Area quadrant ABDC Radius = 14 cm Area o In Fig. Jan 7, 2024 · ∴ Area of remaining part of Square : = Area of Square – Area of 4 quadrants – Area of Circle. 33, ABC is a quadrant of a circle of radius 14 In the figure, ABC is a quadrant of a circle of radius 14 cm and a semicircle is drawn with BC as diameter. [2 MARKS] View Solution Q 3 In the given figure, ABC is a quadrant of a circle of radius 14 cm and a semicircle is drawn with BC as diameter. xpeloj kpciev rswmbnl fvyn ritgcql lqbcj qkc abyxh eax ggvvq